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x^2-0.06x=0.15385
We move all terms to the left:
x^2-0.06x-(0.15385)=0
We add all the numbers together, and all the variables
x^2-0.06x-0.15385=0
a = 1; b = -0.06; c = -0.15385;
Δ = b2-4ac
Δ = -0.062-4·1·(-0.15385)
Δ = 0.619
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.06)-\sqrt{0.619}}{2*1}=\frac{0.06-\sqrt{0.619}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.06)+\sqrt{0.619}}{2*1}=\frac{0.06+\sqrt{0.619}}{2} $
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